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-4.9x^2+18x-16.4=0
a = -4.9; b = 18; c = -16.4;
Δ = b2-4ac
Δ = 182-4·(-4.9)·(-16.4)
Δ = 2.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-\sqrt{2.56}}{2*-4.9}=\frac{-18-\sqrt{2.56}}{-9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+\sqrt{2.56}}{2*-4.9}=\frac{-18+\sqrt{2.56}}{-9.8} $
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